Given a text file
file.txt, print just the 10th line of the file.
file.txt has the following content:
Line 1 Line 2 Line 3 Line 4 Line 5 Line 6 Line 7 Line 8 Line 9 Line 10
Your script should output the tenth line, which is:
sed -n '10 p' file.txt // or sed '10q;d' file.txt
awk 'NR==10' file.txt